Question

is the given function continuous at x=1?
$f(x) = 2x {}^{2} - 3x + 1$
A. No since the value of the function at x = 1 is 4
B. No since the function is undefined at x=1
C. Yes since the function is defined at x=1
D. Yes since the value of the function at x=1 is 4
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Answer 1

Answer:

The answer is "Option C".

Step-by-step explanation:

Given:

$\to f(x)=2x^2-3x+1\\\\when \ x=1\\\\\to f(1)= 2(1)^2-3(1)+1\\\\\to f(1)= 2(1)-3+1\\\\\to f(1)= 2-3+1\\\\\to f(1)=-1+1\\\\\to f(1)=0$

That's why choice C is correct.