Question

Given: in a right triangle, cot0 = 28/45
1. what is csc0
2. what is sec0

Answer 1

Answer:

i)    $cosec0 = \frac{hypotenuse}{opposite side} = \frac{53}{45}$

ii)   $sec0 = \frac{hypotenuse}{adjacent side} = \frac{53}{28}$

Step-by-step explanation:

Step(i):-

Given that    

                 $cot 0 = \frac{28}{45} = \frac{adjacentside}{opposite side}$

Hypotenuse AC² = AB²+BC²

    ⇒             AC² = 45²+28² = 2809

   ⇒             AC = √2809

 ⇒              AC = 53

Hypotenuse  AC =53

Step(ii):-

i)    $cosec0 = \frac{hypotenuse}{opposite side} = \frac{53}{45}$

ii)   $sec0 = \frac{hypotenuse}{adjacent side} = \frac{53}{28}$