Find the missing side using special right triangles
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Answer:
a=4[tex]\sqrt{3}[/tex], b=2[tex]\sqrt{3}[/tex]
Step-by-step explanation:
tan30=b/6, tan30=1/[tex]\sqrt{3}[/tex]
solve for b, b=6*tan30=2[tex]\sqrt{3}[/tex]
sin30=b/a, sin30=1/2
solve for a, a=4[tex]\sqrt{3}[/tex]