Work out the size of angle x.
50°
120°
Х

The value of angle [tex]x[/tex] will be [tex]70^0[/tex] .
A triangle is a polygon with three edges and three vertices. Its angles sum property says that the sum of all angles of a triangle is equals to [tex]180^0[/tex] . i.e.
[tex]\angle A + \angle B + \angle C = 180^0[/tex]
We have,
[tex]\triangle ABC[/tex], in which,
[tex]\angle A =50^0[/tex]
[tex]\angle C =x^0[/tex]
Let, [tex]\angle B =y^0[/tex]
Now,
Work out for [tex]\angle B[/tex],
A straight line always makes an angle of [tex]180^0[/tex] i.e. line [tex]CBD[/tex], which is divided into parts at [tex]B[/tex] by [tex]AB[/tex],
So,
[tex]120^0 + y =180^0[/tex]
[tex]y=180-120[/tex]
[tex]y=60^0[/tex]
Now,
Using angle sum property;
[tex]\angle A + \angle B + \angle C = 180^0[/tex]
[tex]50^0+60^0+x=180^0[/tex]
⇒ [tex]x=180-110[/tex]
[tex]x=70^0[/tex]
Hence, we can say that the measure of [tex]x[/tex] in the triangle will be [tex]70^0[/tex] .
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