Given :-
- Patrick had twice money at first
- Susan recived and Patrick spent some money
- The amount Susan received was 3 times as much as the amount Patrick spent
- At last they have same amount
To Find :-
Solution :-
At first Patrick had twice of Susan.
Hence,
He have 2 × 120 = $240
Let the money received be x
- x + 120 = 3(240 - x)
- x + 120 = 720 - 3x
- 3x + x = 720 - 120
- 4x = 720 - 120
- 4x = 600
- x = 600/4
- x = 150
[tex]\therefore \bold{Susan \: had\:received \: 150\$}[/tex]