Answer:
Q = 52668 J
Explanation:
Given data:
Amount of heat required = ?
Mass of water = 350 g
Initial temperature = 20°C
Final temperature = 56°C
Specific heat capacity of water = 4.18 J/g°C
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 56°C - 20°C
ΔT = 36°C
Q = 350 g× 4.18 J/g°C ×36°C
Q = 52668 J
