Answer:
[tex]\mathbf{I = 0.22 \ amperes}[/tex]
Step-by-step explanation:
From above:
let assume that;
The current is [tex]\dfrac{1}{2}[/tex] ampere when resistance is 240 ohms.
Now, to find the current when R = 540 ohms.
SO; if [tex]I \ \alpha \ \dfrac{1}{R}[/tex]
[tex]I \ =\ \dfrac{k}{R}[/tex] where k = constant
[tex]\dfrac{1}{2} \ =\ \dfrac{k}{240}[/tex]
[tex]2k = 240[/tex]
[tex]k = \dfrac{240}{2}[/tex]
[tex]k = 120[/tex]
Thus; the constant = 120
So; when R = 540 ohms
then the current will be:
[tex]I = \dfrac{k}{R}[/tex]
[tex]I = \dfrac{120}{540}[/tex]
[tex]\mathbf{I = 0.22 \ amperes}[/tex]