Question

An object initially at rest experiences an acceleration
of 1.4 m/s for 5.0 s and then travels at that
constant velocity for another 6.0 s.
Part A
What is the object's average velocity over the 11 s interval?

Answer 1

Answer:

1.4m/s

Explanation:

Average velocity is the total distance covered divided by the total time taken.

 Average velocity  = $\frac{total distance }{time }$  

 Total time taken  = 5s + 6s  = 11s

The first distance covered  = velocity x time  = 1.4 x 5 = 7m

     second distance covered  = velocity x time  = 1.4 x 6  = 8.4m

So;

  Average velocity  = $\frac{7 + 8.4}{11}$    = 1.4m/s