Triangle ABC is an equilateral triangle and O is the center of its inscribed circle. If the area of the circle is 4π cm2, what is the area of triangle ABC?

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Answer:

does one side of equilateral triangle is diameter. I will redo it.

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Answer:

Area of ABC = 16[tex]\sqrt{2}[/tex]

Step-by-step explanation:

if Area of Circle is π·r², which in this case equals 4π, then the radius is 2; this gives us the height of the triangle as 4

since it's a 60-60-60 triangle, the height perpendicular to base creates a 30-60-90 triangle, whose sides are in the ratio of 1 : √2 : 2

therefore the entire base is 4√2 + 4√2 or 8√2

A (ΔABC) = 1/2(4) · 8√2  =  16√2

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