Answer: 3.0 moles of water [tex](H_2O)[/tex] are needed to react with a mole of 3.0 of Na
Explanation:
The balanced chemical reaction of sodium with water is as follows:
[tex]2Na+2H_2O\rightarrow 2NaOH+H_2[/tex]
According to stoichiometry:
2 moles of sodium [tex](Na)[/tex] reacts with = 2 moles of water [tex](H_2O)[/tex]
Thus 3.0 moles of sodium [tex](Na)[/tex] reacts with = [tex]\frac{2}{2}\times 3.0=3.0[/tex] moles of water [tex](H_2O)[/tex]
3.0 moles of water [tex](H_2O)[/tex] are needed to react with a mole of 3.0 of Na
