Answer:
B. ΔAXC ≅ ΔBXC by SSS, so AC ≅ BC because they are corresponding parts of congruent triangles.
Step-by-step explanation:
From the given diagram, XC is common to ΔAXC and ΔBXC.
And it can be observed that CD divides AB into two equal length segments.
Thus,
AX ≅ BX (bisection property of a line)
AC ≅ BC (congruence property of triangles)
Therefore, the congruence relationship between triangles ΔAXC and ΔBXC would be, Side-Side-Side (SSS) so as to show that AC ≅ BC.
