The diagram shows a hexagon-shaped tile used for flooring. Each hexagon tile has an area of 18/3 in 2 Find x.

Answer:
x = 12
Step-by-step explanation:
The hexagonal tile given here is made up of 6 triangles with equal bases and heights.
So, area of hexagonal tile will be equal to 6 times the area of one triangle.
Therefore,
[tex]18 \sqrt{3} = 6 \times \frac{1}{2} \times 2 {( \sqrt{3)} }^{ \frac{x}{12} } . {( \sqrt{3)} }^{ \frac{x}{6} } \\ \\ 18 \sqrt{3} = 6 {( \sqrt{3)} }^{ \frac{x}{12} } . {( \sqrt{3)} }^{ \frac{2x}{12} } \\ \\ \frac{18 \sqrt{3} }{6} = {( \sqrt{3)} }^{ \frac{x}{12} + \frac{2x}{12} } \\ \\ 3 \sqrt{3} = {( \sqrt{3)} }^{ \frac{3x}{12} } \\ \\ 3. {3}^{ \frac{1}{2} } = {3}^{ \frac{3x}{24} } \\ \\ {3}^{1 + \frac{1}{2} } = {3}^{ \frac{x}{8} } \\ \\ {3}^{ \frac{3}{2} } = {3}^{ \frac{x}{8} } \\ (bases \: are \: equal \: so \: exponents \: \\ will \: also \: be \: equal) \\ \implies \frac{3}{2} = \frac{x}{8} \\ \\ x = \frac{3 \times 8}{2} \\ \\ x = 3 \times 4 \\ \\ x = 12[/tex]
The area of the hexagon-shaped tile is the amount of space it occupies
The value of x is 2
The given parameters are:
[tex]\mathbf{Area = 18\sqrt 3}[/tex]
[tex]\mathbf{Base= (\sqrt 3)^{\frac x6}}[/tex]
[tex]\mathbf{Height = 2(\sqrt 3)^{\frac x{12}}}[/tex]
The shape is a regular hexagon (i.e. it has 6 equal sides).
So, the area of one of the segments is the total area divided by 6 and this is calculated as:
[tex]\mathbf{A(1) = \frac{18\sqrt 3}6}[/tex]
[tex]\mathbf{A(1) = 3\sqrt 3}[/tex]
A segment of the hexagon is a triangle, and the area of a triangle is:
[tex]\mathbf{Area = \frac 12 \times Base \times Height}[/tex]
So, we have:
[tex]\mathbf{3\sqrt 3= \frac 12 \times (\sqrt 3)^{\frac x6} \times 2(\sqrt 3)^{\frac{x}{12}}}[/tex]
This gives
[tex]\mathbf{3\sqrt 3= (\sqrt 3)^{\frac x6} \times \sqrt 3)^{\frac{x}{12}}}[/tex]
Apply law of indices
[tex]\mathbf{3\sqrt 3= (\sqrt 3)^{\frac x6 + \frac{x}{12}}}[/tex]
Add the exponents
[tex]\mathbf{3\sqrt 3= (\sqrt 3)^{\frac x4}}[/tex]
Express the equations as a base of 3
[tex]\mathbf{3^{\frac 32}= 3^{\frac x8}}[/tex]
Cancel out the base
[tex]\mathbf{\frac 32= \frac x8}[/tex]
Multiply through by 8
[tex]\mathbf{12= x}[/tex]
Rewrite as:
[tex]\mathbf{x = 12}[/tex]
Hence, the value of x is 2
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