Question

In triangle ABC, a = 5.3 cm, b = 4.8 cm, and c = 9.2 cm.

Determine the measures of the three interior angles of triangle ABC.

PLZ HELP

Answer 1

Answer:

a= 25.69, b=23.12, c=131.119

Step-by-step explanation:

$cosa=\frac{B^{2} +C^{2} -A^{2} }{2BC} \\ =\frac{79.59}{88.32} \\ a = 25.69$

$cos(b)=\frac{A^{2} +C^{2} -B^{2} }{2AC} \\ =\frac{89.69}{97.52}\\ b=23.12\\c=180-23.12-25.69\\ = 131.119$