Find the value of x.

Answer:
[tex]\boxed {\boxed {\sf x=5}}[/tex]
Step-by-step explanation:
We are given a quadrilateral. It will be difficult to find x using this shape, but we can drop a perpendicular line and create a right triangle (refer to the attached image).
Match up the other sides. The height is equal to 4.
At the base, the longer portion is 7 because the line segment above the base is 7. Since the entire base is 10, the smaller portion must be 3 because 10-7=3.
Now we have 2 sides of a right triangle and one unknown. We can use the Pythagorean Theorem.
[tex]a^2+b^2=c^2[/tex]
Where a and b are the legs and c is the hypotenuse.
In this triangle, 4 and 3 are the legs because they make the right angle. x is the hypotenuse because it is opposite the right angle.
Substitute the values into the formula.
[tex](4)^2+(3)^2=x^2[/tex]
Solve the exponents.
[tex]16+(3)^2=x^2[/tex]
[tex]16+9=x^2 \\[/tex]
[tex]25=x^2[/tex]
Take the square root of both sides of the equation to isolate the variable.
[tex]\sqrt{25} =\sqrt{x^2}[/tex]
[tex]5=x[/tex]
x is equal to 5.