Respuesta :

Space

Answer:

100 g O₂

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Chemistry

Atomic Structure

  • Reading a Periodic Table

Stoichiometry

  • Using Dimensional Analysis

Explanation:

Step 1: Define

4 mol O₂

Step 2: Identify Conversions

Molar Mass of O - 16.00 g/mol

Molar Mass of O₂ - 2(16.00) = 32.00 g/mol

Step 3: Convert

  1. Set up:                     [tex]\displaystyle 4 \ mol \ O_2(\frac{32.00 \ g \ O_2}{1 \ mol \ O_2})[/tex]
  2. Multiply:                   [tex]\displaystyle 128 \ g \ O_2[/tex]

Step 4: Check

Follow sig fig rules and round. We are given 1 sig fig.

128 g O₂ ≈ 100 g O₂

ACCESS MORE
EDU ACCESS