Question

A sample of blood plasma occupies 0.550 L at 0'C and 1.03 bar, and is compressed isothermally by 0.57 per cent by being subjected to a constant external pressure 95.2 bar. Calculate w.

Answer 1

Answer:

Following are the solution to this question:

Explanation:

The first volume of its blood products analysis is $V_i = 0.550\ dm^3$at a temperature of 0° C. In the isothermal expansion of its sample data in a $0.57\%$ reduction of its size; the actual sample size is thus

$V_f = [(0.550) - 0.57 \% \ of (0.550)] dm^3$

    $= [(0.550)-(\frac{0.57}{100}) \times (0.550)] \ dm^3 \\\\= [(0.550)-(0.0057) \times (0.550)] \ dm^3 \\\\= [0.550-0.003135] \ dm^3 \\\\= 0.546865 \ dm^3$

It is used to persistent the external pressure toward $P_{ext}$ was = $\overline{95.2}$. It is the job completed is, therefore,

$W = - P_{ext} \times (V_f -V_i)$

    $= -(\overline{95.2}) \times (0.546865 -0.550) \ dm^3 \\\\ = \overline{0.2899875} \ dm^3 \\\\ = \overline{0.290} \ dm^3$