Which equation is y = 2x2 – 8x + 9 rewritten in vertex form?


A. y = 2(x – 2)2 + 9
B. y = 2(x – 2)2 + 5
C. y = 2(x – 2)2 + 1
D. y = 2(x – 2)2 + 17

Respuesta :

I hope this helps you



y= 2 (x^2-4x+4)+1


y=2 (x.x-2.2.x+(-2). (-2))+1


y= 2. (x-2)^2+1

we have

[tex] y=2x^{2} -8x+9 [/tex]


Group terms that contain the same variable, and move the constant to the opposite side of the equation

[tex] y-9=2x^{2} -8x [/tex]


Factor the leading coefficient

[tex] y-9=2(x^{2} -4x) [/tex]


Complete the square. Remember to balance the equation by adding the same constants to each side

[tex] y-9+8=2(x^{2} -4x+4) [/tex]

[tex] y-1=2(x^{2} -4x+4) [/tex]


Rewrite as perfect squares

[tex] y-1=2(x-2)^{2} [/tex]

[tex] y=2(x-2)^{2} +1 [/tex]-----> equation in vertex form


therefore


the answer is the option C

[tex] y=2(x-2)^{2} +1 [/tex]


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