Respuesta :
I hope this helps you
y= 2 (x^2-4x+4)+1
y=2 (x.x-2.2.x+(-2). (-2))+1
y= 2. (x-2)^2+1
y= 2 (x^2-4x+4)+1
y=2 (x.x-2.2.x+(-2). (-2))+1
y= 2. (x-2)^2+1
we have
[tex] y=2x^{2} -8x+9 [/tex]
Group terms that contain the same variable, and move the constant to the opposite side of the equation
[tex] y-9=2x^{2} -8x [/tex]
Factor the leading coefficient
[tex] y-9=2(x^{2} -4x) [/tex]
Complete the square. Remember to balance the equation by adding the same constants to each side
[tex] y-9+8=2(x^{2} -4x+4) [/tex]
[tex] y-1=2(x^{2} -4x+4) [/tex]
Rewrite as perfect squares
[tex] y-1=2(x-2)^{2} [/tex]
[tex] y=2(x-2)^{2} +1 [/tex]-----> equation in vertex form
therefore
the answer is the option C
[tex] y=2(x-2)^{2} +1 [/tex]