The horizontal asymptote of the equation y=[tex](3x-1)/(x+3)[/tex] is 3.
Given an equation y=[tex](3x-1)/(x+3)[/tex] and we are required to find the horizontal asymptote of the equation.
Equation is like a relationship between two or more variables expressed in equal to form. It may be linear equation, quadratic equation or cubic equation. Equation of two variables look like ax+by=c.
Put x=0 in the equation,
y=[tex](3x-1)/(x+3)[/tex]
Horizontal asymptote can be found by dividing the coefficients of the leading terms of the equation. We have to divide the coefficients.
Horizontal asymptote=3x/x
=3
Hence the horizontal asymptote of the equation y=[tex](3x-1)/(x+3)[/tex] is 3
Learn more about horizontal asymptote at https://brainly.com/question/4138300
#SPJ1
