The alcohol is likely to be first deprotonated by the strong base, generating an alkoxide ion, which can then undergo intramolecular SN2 reaction to afford the observed product, a cyclic ether. Cl .. OH .. NaH H2 Cl .. + O : Na .. O NaCl
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.