Mass of Li₂O= 719.809 g
Given
1,060 g of CO₂
Required
Mass of Li₂O
Solution
Reaction
Possible compound : Li₂O
Li₂O(aq) + CO₂(g) → Li₂CO₃(aq)
mol CO₂(MW=44 g/mol) :
= 1,060 g : 44 g/mol
= 24.09
From the equation, mol ratio of LiO : CO₂ = 1 : 1, so mol Li₂O : 24.09
Mass Of Li₂O(MW=29.88 g/mol) :
= mol x MW
= 24.09 x 29.88
= 719.809 g