Question

Please guys I am begging you to help me! This was due yesterday and I need help! SO please help!
3. Given a right triangle DEF with angle D as a right angle, find side DE if DF = 5 units and EF = 13 units.

4. Given a right triangle PQR with angle R as 90 degrees and angle Q as 54 degrees, find side PR if side RQ is 4.6 units.

5. Given a right triangle ABC with angle C as 90 degrees, find angle A if side AC = 3.0 units and BC = 6.8 units and AC = 3.0 units, find angle A.

Answer 1

Answer:

• Q3. 12 units
• Q4. 6.33 units
• Q5. 66.19°

Step-by-step explanation:

Q3

DE and DF are legs and EF is hypotenuse

• DE = √EF² - DF²
• DE = √13² - 5² = √169 - 25 = √ 144 = 12
• DE = 12 units

Q4

PR is opposite side of angle Q and RQ is adjacent side

• tan 54 = PR/RQ
• tan 54 = PR / 4.6
• PR = 4.6tan 54
• PR = 6.33 units

Q5

As previous question, using tan as BC is opposite and AC is adjacent leg of angle A

• tan A = 6.8/3
• tan A = 2.266
• A = arctan (2.266)
• A = 66.19°