Question

1.Write an equation of the line in point-slope
form, slope-intercept form. AND standard form
that passes through the point (-1,10) and has
slope = -6.

Answer 1

Answer:

Point slope form

$y-10 = -6 (x+1)$

Slope-intercept form

$y=-6x+4$

Standard form

$4x+y=4$

Step-by-step explanation:

Equation in Point slope form is

$y-y_1=m (x-x_1)$ ---------- (1)

Here

$m=-5 \ \ \ and \ \ \ (x_1, y_1) = (-1, 10)$

Substituting values in equation (1)

$y-10 = -6 (x+1)$ ------------- (2)

Equation (2) is equation of line in point slope form.

Re-arranging equation (2)

$y = -6x - 6 + 10$

$y=-6x+4$ ----------- (3)

Equation (3) is equation of straight line in slope-intercept form

Re-arranging equation (3)

$4x+y=4$   --------(4)

Equation (4) is equation of line in standard form