Question

Which of the following gives the correct intercept points and vertex point for the function f(x) = x2 - 4x-5?
A. y-intercept: (0,5); vertex point: (-2,9); x-intercepts: (1,0) and (5,0)
B. y-intercept: (0,-5); vertex point: (2,-9); x-intercepts: (-1,0) and (5,0)
C. y-intercept: (0,5); vertex point: (2,-9); x-intercepts:(-1,0) and (-5,0)
D. y-intercept: (0,-5); vertex point: (-2,-9); x-intercepts: (1,0) and (-5,0)​

Answer 1

Answer:

its b

Step-by-step explanation:

Answer 2

The y-intercept: (0,-5); vertex point: (2,-9); x-intercepts: (-1,0) and (5,0) option (B) is correct.

What is a parabola?

It is defined as the graph of a quadratic function that has something bowl-shaped.

We have a function:

$\rm f(x) = x^2 - 4x-5$

The above function shows a parabola equation.

For y-intercept plug x = 0 in the function.

f(0) = -5

So the y-intercept is (0, -5)

For the vertex:

$\rm f(x) = (x-2)^2-9$  (from perfect square trinomial)

$\rm f(x) = (x-h)^2+k$

(h, k) is the vertex = (2, -9)

For x-intercept:

f(x) = 0

$\rm x^2 - 4x-5=0$

After factorizing:

(x+1)(x-5) = 0

So the x-intercept will be:

(-1, 0) and (5, 0)

Thus, the y-intercept: (0,-5); vertex point: (2,-9); x-intercepts: (-1,0) and (5,0) option (B) is correct.

Know more about the parabola here:

brainly.com/question/8708520

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