Answer:
The solution to the equation is:
[tex]x=4,\:x=\frac{3}{2}[/tex]
Step-by-step explanation:
Given the equation
[tex]3\left(x-4\right)\left(2x-3\right)=0[/tex]
Using the zero factor principle
if ab=0, then a=0 or b=0 (or both a=0 and b=0)
[tex]x-4=0\quad \mathrm{or}\quad \:2x-3=0[/tex]
now solving
[tex]x - 4 = 0[/tex]
adding 4 to both sides
[tex]x - 4 + 4 = 0 + 4[/tex]
simplifying
[tex]x = 4[/tex]
and also solving
[tex]2x - 3 = 0[/tex]
adding 3 to both sides
[tex]2x - 3 + 3 = 0 + 3[/tex]
simplifying
[tex]2x = 3[/tex]
divide both sides by 2
[tex]\frac{2x}{2}=\frac{3}{2}[/tex]
simplifying
[tex]x=\frac{3}{2}[/tex]
Therefore, the solution to the equation is:
[tex]x=4,\:x=\frac{3}{2}[/tex]
Answer:
4 or 3/2
Step-by-step explanation:
I had this question on a quiz, I got it correct.
