A 0.145 kg baseball is thrown with a velocity of 25.0 m/s. How much work was done on the baseball to bring it from rest to 25.0 m/s? [Neglect air resistance]

Respuesta :

Answer:

45.31 J

Explanation:

We are given that

Mass of baseball , m=0.145 kg

Initial velocity, u=0

Final velocity, v=25 m/s

We have to find the work done on the baseball to bring it from rest to 25 m/s

We know that

Work done = Change in kinetic energy

Work done, W=[tex]\frac{1}{2}m(v^2-u^2)[/tex]

Using the formula

Work done, W[tex]=\frac{1}{2}(0.145)((25)^2-0)[/tex]

Work done=[tex]\frac{1}{2}(0.145)(625)[/tex]

Work done, W=45.31 J

Hence, the work done on the baseball to bring it from rest to 25 m/s

=45.31 J

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