Answer:
Change in kinetic energy=-513.652 KJ
Change in potential energy=431.64KJ
Explanation:
We are given that
Mass of an automobile , m=1100 kg
Initial speed, u=110 km/h=[tex]110\times \frac{5}{18}=30.56 m/s[/tex]
Where [tex]1 km/h=5/18 m/s[/tex]
Height , [tex]h_2=40 m[/tex]
[tex]g=9.81 m/s^2[/tex]
Final speed, v=0
Change in kinetic energy,[tex]\Delta K.E=\frac{1}{2}m(v^2-u^2)[/tex]
[tex]\Delta K.E=\frac{1}{2}(1100)(0-(30.56)^2)=-513652.48 J[/tex]
[tex]\Delta K.E=-\frac{513652.48}{1000}=-513.652 KJ[/tex]
Where 1 KJ=1000 J
Change in potential energy,[tex]\Delta P.E=mgh(h_2-h_1)[/tex]
Initially height, h1=0
Using the formula
[tex]\Delta P.E=1100\times 9.81(40-0)[/tex]
[tex]\Delta P.E=431640J[/tex]
[tex]\Delta P.E=431.64KJ[/tex]