Answer:
87% bromine and 13% magnesium
Explanation:
The compound contained 32.0 grams of bromine and 4.9 grams of magnesium.
We need to find its percent composition.
Mass of the sample = mass of bromine + mass of magnesium
= 32 g + 4.9 g
= 36.9 g
Percentage composition of bromine,
[tex]\%=\dfrac{32}{36.9}\times 100\\\\=86.7\\\\=87\%[/tex]
The percentage composition of magnesium,
[tex]\%=\dfrac{4.9}{36.9}\times 100\\\\=13.27\\\\=13\%[/tex]
So, its percent composition is 87% bromine and 13% magnesium.
