Answer:
the correct answer is B r =√2 R
Explanation:
To solve this exercise we will use the force of gravity, at two points when the rocket is on the platform and when it is at the desired height.
Rocket with cargo on the platform
[tex]F_{g} = G \frac{ m M }{R^2} = W[/tex]
where m is the mass of the rocket and the charge, M the mass of the earth and R the distance from the center of the earth
Rocket loaded at desired height
[tex]F_{g} = G \frac{m M}{r^2 } = \frac{W}{2}[/tex]
we write our two equations
W = g m M / R²
[tex]\frac{W}{2}[/tex] = G m M / r²
we match to solve them
Gm M / R² = 2 Gm M / r²
1 / R² = 2 / r²
r =√2 R
therefore the correct answer is B