Answer:
Minimum 3 squares.
Step-by-step explanation:
Let the number of identical squares that will fit in the rectangle = x
Sum of the area of the squares = Area of the given rectangle
x(Side length of the square)²= (length of the rectangle × width of the rectangle)
x(S)²= (40 × 90)
x(S)²= 3600 cm²
For the minimum numbers of the squares,
If x = 1,
S = √3600 = 60 cm
But the length of the rectangle is 40 cm, so can't be fitted in the rectangle.
If x = 2,
2S² = 3600
S² = 1800
S = √1800
S = 42.43 cm
Since, length of the rectangle is 40 cm, so the given square can't be fitted in the rectangle.
If x = 3,
3S² = 3600
S² = 1200
S = √1200
= 34.64 cm
Therefore, minimum 3 squares can be fitted in the given rectangle.
