Answer:
12
Step-by-step explanation:
The given expression is :
[tex]\dfrac{j^3k}{h^0}[/tex]
We need to find the value of this expression when h = 8, j = -1 and k = -12.
Put all the values in the given expression.
[tex]\dfrac{j^3k}{h^0}\\\\=\dfrac{(-1)^3\times (-12)}{(8)^0}\\\\=\dfrac{-1\times -12}{1}\\\\=12[/tex]
So, the value of the given expression is 12.