Given that CA = CB and m∠CPB = 90 degrees, which statement can you conclude is true?

CP is the perpendicular bisector, the correct option is C.
A line that bisects another line at 90 degree is called a perpendicular bisector.
The line CP is making an angle of 90 degree on the line AB
CA = CB (given)
CP =CP (Common)
∠CPB = ∠CPA = 90 ( Linear Pair)
Triangle CPA ≅ CPB, by SSA Congruence
Therefore by CPCTC, AP =PB
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