Answer:
[tex]m=25.20gNO[/tex]
Explanation:
Hello!
In this case, since the STP conditions are known as 273.15 K of temperature and 1.00 atm of pressure, we can use the ideal gas equation to compute the moles of NO gas first:
[tex]PV=nRT\\\\n=\frac{PV}{RT}=\frac{1.00atm*18.82L}{0.08206\frac{atm*L}{mol*K}*273.15K}=0.8396molNO[/tex]
Next, since the molar mass of NO is 30.01 g/mol the resulting mass in grams is:
[tex]m=0.8396 molNO*\frac{30.01gNO}{1molNO}\\\\m=25.20gNO[/tex]
Which has four significant figures.
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