Okie, let's think about this first, since it needs some thinking before we can actually solve this bad boy. Let's start with the first number being x.
First number = x
Second number = x + 1
Third number = x + 2
So the sum would be ( x ) + ( x + 1 ) + ( x + 2 ) = 996
3x + 3 = 996
3x = 993
x = 331
331 for the first number.
332 second number
333 third number. Let't check.
331+ 332 + 333 = 996 yup
Therefore the three consecutive numbers are 331,332,333.
I hope this helps :-)
