Question

Write an equation of a line that passes through the point (2,0) and is perpendicular to the line y=−12x+3.

Answer 1

Answer:

Equation of a line that passes through the point (2,0) and is perpendicular to the line y=−12x+3 is

$y = 2x-4$

Step-by-step explanation:

Slope of the line y=−12x+3 is m1=-12

We know slopes of perpendicular lines are negative reciprocals of each other. Therefore m2=2

Equation of line in point slope form is

$y-y_1 = m_2 (x-x_1)$ ----------- (1)

Here

$m_2 = 2 \ \ \ and \ \ \ (x_1, y_1) = (2, 0)$

Substituting values in equation  (1)

$y-0 = 2 (x-2)$

$y = 2x-4$