Question

Harriet buys lunch at school every day. She always gets
pizza when it is available. The cafeteria has pizza about 80% of the time.

Harriet runs a simulation to model this using a random
number generator. She assigns these digits to the possible outcomes for each day of the week:

• Let 0 and 1 = no pizza available

• Let 2, 3, 4, 5, 6, 7, 8, and 9 = pizza available

The table shows the results of the simulation.

Group number
Random digits
1: 19223
2: 73676
3: 45467
4: 52711
5: 95592

Group number
Random digits
6: 68417
7: 82739
8: 60940
9: 36009
10: 38448

What is the estimated probability that Harriet will eat pizza for lunch
every day next week?

A. 7/10 = 70%
B. 4/10 = 40%
C. 5/10 = 50%
D. 0/10 = 0%

Answer 1

The estimated probability that Harriet will eat pizza for lunch every day next week is 5/10 = 50%

How to determine the probability?

The simulation is represented as:

• 0 and 1 represents when pizza is not available
• 2 to 9 represents when pizza is available

The above means that the simulation that represents when she eats pizza for lunch must have all its digits to be from 2 to 9.

The results that represent eating pizza for lunch are:

73676 45467 95592 82739 38448

The count of the result is 5.

Hence, the probability is 5/10 = 50%

Read more about probabiity at:

https://brainly.com/question/251701

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