Answer:
[tex]x >\ or\ =\ \frac{7}{9}[/tex]
Step-by-step explanation:
[tex]We\ are\ given\ that,\\4x+8>\ or =\ 5(3-x)\\Hence,\\We\ can\ treat\ inequality\ in\ the\ same\ way\ we\ do\ for\ solving\ equalities.\\Hence,\\4x+8>\ or\ =\ 5(3-x)\\By\ simplifying\ the\ RHS,\\4x+8 >\ or\ =\ 15-5x\\Hence,\\Adding\ (+5x)\ to\ the\ LHS\ and\ RHS,\\4x+8+(5x) >\ or\ =\ 15-5x+(5x)\\Simplifying,\\5x+4x+8 >\ or\ =\ 15+(5x-5x)\\9x+8 >\ or\ =\ 15\\Adding\ (-8)\ to\ both\ LHS\ and\ RHS,\\9x+8+(-8) >\ or\ =\ 15+(-8)\\Simplifying,\\9x+(8-8) >\ or\ =\ 7\\[/tex]
[tex]9x >\ or\ =7\\x >\ or\ =\ \frac{7}{9}[/tex]
Step-by-step explanation:
4x+8≥5(3-x)
4x+8≥15-5x
adding 5x on each term
4x+5x+8≥15-5x+5x
9x+8≥15
subtract each term by 8
9x+8-8≥15-8
9x≥7
dividing each term by 9
9x/9=7/9
x≥7/9
is your answer
