Question

Find the distance between points P(6, 2) and Q(5, 9) to the nearest tenth.

Answer 1

Answer:

$d = 10$

Step-by-step explanation:

Distance formula

$d =\sqrt{(x_2-x_1)^{2} + (y_2-y_1)^{2} }$        ------------ (1)

Here

$(x_1, y_1) = (6, 2) \ \ \ and \ \ \ (x_2, y_2) = (5, 9)$

Substituting values in equation (1)

$d =\sqrt{(5-6)^{2} + (9-2)^{2} }$

$d =\sqrt{(-1)^{2} + (7)^{2} }$

$d = \sqrt { 50 }$

$d=7.07$

the nearest tenth is 10