Question

When 3.00 moles of hydrogen molecules and 1.50 moles of oxygen molecules react, they form 3.00 moles of water
according to the reaction below.
2H, + O2 + 2H2O
How many grams of oxygen were required?

Answer 1

Answer:

Mass = 48 g

Explanation:

Given data:

Number of moles of H₂ react= 3.00 mol

Number of moles of O₂ react= 1.50 mol

Number of moles of water formed = 3.00 mol

Mass of oxygen react = ?

Solution:

Chemical equation:

2H₂ + O₂    →      2H₂O

It is stated in given question when 1.50 moles of oxygen react 3.00 moles of water are formed. Thus, mass of 1.50 moles of oxygen is

Mass of oxygen:

Mass = number of moles × molar mass

Mass = 1.50 mol × 32 g/mol

Mass = 48 g