Answer:
3065.4J
Explanation:
Given parameters:
Mass of water = 335g
Initial temperature = 24.5°C
Final temperature = 26.4°C
Unknown:
How much heat is absorbed by the sample = ?
Solution:
To solve this problem, we use the expression below:
Heat absorbed = mass x specific heat of water x change in temperature
The specific heat of water = 4.816J/g°C
So;
Heat absorbed = 335 x 4.816 x (26.4 - 24.5) = 3065.4J
