Question

An isotope of cesium (cesium-137) has a half-life of 30 years. If 1.0 g of cesium-137 disintegrates over a period of 90 years, how many g of cesium-137 would remain?​

Answer 1

Answer:

3 half-lives 7. An isotope of Cesium (Cesium-137) has a half life of 30 years. If 1.0 mg of cesium-137 disintegrates over a period of 90 years, how many mg of cesium-137 would remain? of sodium-25 is 60 seconds? : 3 minutes t=601 = 3 half-lives 5.0mg ~ 2.5 mg + 1.25mg →) 625 mg.

Explanation:

Hope this helps

Answer 2

• To find the mass in grams of Cesium that would remain after disintegration, we would be applying the formula:

• N(t) = $N_{0} (\frac{1}{2})^{\frac{t}{t{\frac{1}{2} } }$

       where:

      $N_{0}$ = Initial quantity of the sample = 1.0g

       t = time in years of disintegration = 90 years

      $t\frac{1}{2}$ = Half life of cesium isotope = 30 years

      N(t) = Quantity of substance after disintegration = ?

• Solving for N(t)

N(t) =  $1 ( \frac{1}{2})^ \frac{90}{30}$

N(t) =  $1 (\frac{1}{2})^{3}$

N(t) = 0.125 grams

Therefore, the quantity of cesium-137 that would remain after disintegrating over a period of 90 years is 0.125 grams.

To learn more, visit the link below:

https://brainly.com/question/22608626