Answer:
Step-by-step explanation:
Domain has all values of x ( think X marks the spot on your domain) so the restrictions come in those cases from the fact that a fraction can NOT have the denominator 0 because dividing by 0 is not allowed.
5.
here x+1 [tex]\neq[/tex] 0 and x+3 [tex]\neq[/tex] 0 so the domain restrictions are x [tex]\neq[/tex] -1 and x[tex]\neq[/tex] -3
to solve you need to factor x^2 -6x-27
you can do it by using
x^2 - Sx +P = 0 where S= root 1 +root 2 and P = root 1*root2
so in our case Sum has to be 6 and Product -27, what 2 numbers add to 6 and their product is -27? ....-3 and 9; S= -3+9 = 6 and P= -3*9 = -27
it will factor in (x-root 1) (x-root 2)
x^2 -6x-27 = (x+3)(x-9)
[tex]\frac{(x+3)(x-9)}{x+1} * \frac{x+1}{x+3} =\\[/tex]
simplify x+1 and x+3
x-9
