We have 6 moles of C (2*3=6), 14 moles of H (2*7=14) and 1 mol of O in 1 mol of (C₃H₇)₂O:
Therefore:
1 mol of (C₃H₇)₂O-------------6 moles of C
0.185 moles of (C₃H₇)₂O------ x
x=(0.185 moles * 6 moles)/1 mole=1.11 moles
Answer: there are 1.11 moles of C in 0.185 moles of dipropyl ether
1 mol of C-----------------6.022*10²³ atoms
1.11 moles of C------------ x
x=(1.11 moles of C *6.022*10²³ atoms)/1 mole of C=6.68 *10²³ atoms
Answer: there are 6.68*10²³ atoms of C in 0.185 moles of dipropyl ether.
1 mole of (C₃H₇)₂O-------------14 moles of H
0.185 moles of (C₃H₇)₂O------ x
x=(0.185 moles * 14 moles)/1 mole=2.59 moles
there are 2.59 moles of H in 0.185 moles of dipropyl ether
1 mol -----------------------6.022*10²³ atoms
2.59 moles----------------- x
x=(2.59 moles * 6.022*10²³ atoms)/1 mol=1.56*10²⁴ atoms
Answer: there are 1.56*10²⁴ atoms in 0.185 moles of dipropyl ether.
1 mol of (C₃H₇)₂O-------------1 moles of C
0.185 moles of (C₃H₇)--------- x
x=(0.185 moles *1mol)/1 mol=0.185 moles
Answer: there are 0.185 moles of O in 0.185 moles of dipropyl ether.
