PLEASE HELP!!!!!! (20 POINTS)
In ΔDEF, d = 740 inches, f = 690 inches and ∠F=47°. Find all possible values of ∠D, to the nearest degree.

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Answer:

Step-by-step explanation:

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In triangle DEF, the all possible values of ∠D is 52⁰ and 128⁰.

What is triangle?

A triangle is "closed, 2D shape with 3 sides, 3 Angles and 3 vertices".  

According to the question,

In ΔDEF, d = 740 inches, f = 690 inches and ∠F = 47°

Law of sines is [tex]\frac{a}{sinA}[/tex] = [tex]\frac{b}{sinB}[/tex] = [tex]\frac{c}{sinC}[/tex] where a, b, c are sides of the triangle and A, B, C are angles of the triangle.

Using Law of sines and applying reciprocal we get   [tex]\frac{sinA}{a}[/tex]=[tex]\frac{sinB}{b}[/tex] .

a = d = 740 inches, b = f = 690 inches, ∠A=∠D and ∠B = ∠F.

∠F = 47°.

[tex]\frac{sinD}{740}[/tex]=[tex]\frac{sin47}{690}[/tex] .

[tex]sinD = \frac{740sin47}{690}[/tex] ≈ 0.7843

[tex]D = sin^-1(0.7843)[/tex] ≈ 51.66 = 52°

Quadrant II: 180° - 52° = 128°.

To check for possibility

47° + 52° =99°   [This is possible because 99° is less than 180°]

47° + 128° =175°  [This is possible because 175° is less than 180°]

Hence, the triangle DEF, the all possible values of ∠D is 52⁰ and 128⁰.

Learn more about Triangle here

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