Question

Given that f(x) = 2x+4 and h(x)= x3, find (h of)(1).

Answer 1

Answer:

Solution,

Given,

f(x) = 2x + 4

h(x) = $x^{3}$

Now,

hof(x) = h{f(x)} = h (2x + 4) = $(2x+4)^{3}$

Put x = 1,

hof(1) = $[2(1)+4]^{3}$ = 216