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A ball was rolling downhill at 2 m/s. After 5s, it was rolling at 90 m/s. What is its acceleration?

Respuesta :

Answer:

17.6 m/s²

Explanation:

Given:

[tex]v_{f}[/tex] = 90 m/s (final velocity)

[tex]v_{i}[/tex] = 2 m/s (initial velocity)

Δt = 5s (change in time)

The formula for acceleration is:

[tex]a_{avg}[/tex] = Δv / Δt

We can find Δv by doing

Δv = [tex]v_{f}[/tex] - [tex]v_{i}[/tex]

Replace the values

Δv = 90m/s - 2m/s

Δv= 88m/s

Using the equation from earlier, we can find the acceleration by dividing the average velocity by time.

[tex]a_{avg}[/tex] = Δv / Δt

[tex]a_{avg}[/tex] = [tex]\frac{88m/s}{5/s}[/tex]

acceleration = 17.6 [tex]m/s^{2}[/tex]

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