Answer:
See Explanation
Step-by-step explanation:
Your question is incomplete, as the equations or graph or table(s) were not given.
However, I'll give a general way of solving this.
Take for instance, the equations are:
[tex]y = \frac{4}{3}x - 1[/tex]
[tex]y = \frac{2}{3}x - \frac{1}{2}[/tex]
To do this, we start by equating both equations.
[tex]y = y[/tex]
i.e.
[tex]\frac{4}{3}x - 1= \frac{2}{3}x - \frac{1}{2}[/tex]
Collect Like Terms
[tex]\frac{4}{3}x - \frac{2}{3}x= 1 - \frac{1}{2}[/tex]
Take LCM
[tex]\frac{4x- 2x}{3}= \frac{2 - 1}{2}[/tex]
[tex]\frac{2x}{3}= \frac{1}{2}[/tex]
Cross Multiply
[tex]2x * 2 = 3 * 1[/tex]
[tex]4x = 3[/tex]
Make x the subject
[tex]x = \frac{3}{4}[/tex]
Substitute 3/4 for x in [tex]y = \frac{4}{3}x - 1[/tex]
[tex]y = \frac{4}{3} * \frac{3}{4} - 1[/tex]
[tex]y = 1 - 1[/tex]
[tex]y = 0[/tex]
Hence:
[tex](x,y) = (\frac{3}{4},0)[/tex]
