Question

x+3y=0 and 12y=-4 equation plz help.

Answer 1

Answer:

$x = 1$ and $y = -\frac{1}{3}$

Step-by-step explanation:

So we can equate the second equation in terms of y by dividing both sides by 12:

$y = -\frac{1}{3}$

Let us substitute this into the first equation:

$x + 3y = 0$  

then becomes  

$x + 3(-\frac{1}{3} ) = 0$

which simplifies to

$x - 1 = 0$

Finally solving for x gives us:

$x = 1$

Therefore, $x = 1$ and $y = -\frac{1}{3}$

Hope this helps!

Brainliest please!

Answer 2

Answer:

x=1, y=-1/3

Step-by-step explanation:

x+3y=0

12y=-4

12y=-4

y=-1/3

x+3y=0

x+3(-1/3)=0

x-1=0

x=1