Simon Schama identified four elements to the new revolutionary state and comments that the items on that list "could equally describe the France of Louis XIV." Give one specific example from any of those four elements that were true in Louis XIV's France.

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Answer:

Answer:

Reorder the terms:

8 + 6p + -4p = 3(p + 4)

Combine like terms: 6p + -4p = 2p

8 + 2p = 3(p + 4)

Reorder the terms:

8 + 2p = 3(4 + p)

8 + 2p = (4 * 3 + p * 3)

8 + 2p = (12 + 3p)

Solving

8 + 2p = 12 + 3p

Solving for variable 'p'.

Move all terms containing p to the left, all other terms to the right.

Add '-3p' to each side of the equation.

8 + 2p + -3p = 12 + 3p + -3p

Combine like terms: 2p + -3p = -1p

8 + -1p = 12 + 3p + -3p

Combine like terms: 3p + -3p = 0

8 + -1p = 12 + 0

8 + -1p = 12

Add '-8' to each side of the equation.

8 + -8 + -1p = 12 + -8

Combine like terms: 8 + -8 = 0

0 + -1p = 12 + -8

-1p = 12 + -8

Comb[tex]\lim_{n \to \infty} a_n \lim_{n \to \infty} a_n[/tex]

Explanation:

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