let the probability that 37 will in the first group be q and probability 89 will be in the second group be s. since quality and s are independent events,
p (q)=1/50
p (s)=1/50
thus p (QnS)=(1/50)(1/50)
=
=1/2500
therefore the probability that 37 & 89 will be in the same group is 1/2500