Drag numbers to write an equation for the line in slope-intercept form. Numbers may be used once, more than once, or not at all.

Graph of a diagonal line with x-axis and y-axis. A line is passing through co-ordinates (0,5) and (2,-3).

Drag numbers to write an equation for the line in slopeintercept form Numbers may be used once more than once or not at all Graph of a diagonal line with xaxis class=

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Answer:

y = -4x + 5

Step-by-step explanation:

Here, we want to get the equation of the line that passes through the given points

The general form is;

y = mx + b

where m is the slope and b is the y intercept

To find the slope, we use the slope formula

this is ;

m = (y2-y1)/(x2-x1)

(x1,y1) = (0,5)

(x2,y2) = (2,-3)

m = (-3-5)/(2-0) = -8/2 = -4

To get the y-intercept we simply substitute one of the points

But we know that the y-intercept is the y-value when x = 0

From the point we can see (0,5) which means that the y-intercept is 5

so the equation of the line is;

y = -4x + 5

The equation of the graph in slope intercept form is y = -4x + 5

Using slope intercept equation

y = mx + b

where

m = slope

b = y- intercept

Therefore,

Let's take 2 coordinates to get the slope.

(1, 1)(0, 5)

y-intercept  = 5

Therefore,

m = 5 - 1 / 0 - 1 = - 4

y = -4x + 5

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